Q: What are the seven layers of the OSI model?
A: The layers are physical, data link, network, transport, session, presentation, and application layers.
Q: In the TCP client-servel model, how does the three-way handshake work in opening connection?
A: The client first sends a packet with sequence "x" to the server. When the server receives this packet, the server will send back another packet with sequence "y", acknowledging the request of the client. When the client receives the acknowledgement from the server, the client will then send an acknowledge back to the server for acknowledging that sequence "y" has been received.
Q: What is the purpose of exchanging beginning sequence numbers during the the connection in the TCP client-server model?
A: To ensure that any data lost during data transfer can be retransmitted.
Q: How does Asynchronous Transfer Mode (ATM) work?
A: ATM works by transmitting all traffic in small, fixed-sized cells. These small, fixed-size cells reduces queuing delay and can be switched quickly. ATM fits into layer 2 of the OSI model and provides functions for framing and error correction. At the port interface, ATM switches convert cells into frames, and vice versa. ATM provides Quality of Service and traffic shaping.
Q: Given a Class B Network with subnet mask of 255.255.248.0 and a packet addressed to 130.40.32.16, what is the subnet address?
A: Take the 2 addresses, write them in binary form, then AND them. The answer is 130.40.32.0
6 Comments on Networking and protocols interview questions
How duplicated packets are generated in the network?
Answer: Due to re-transmissions
This is regarding the question :-
Q: Given a Class B Network with subnet mask of 255.255.248.0 and a packet addressed to 130.40.32.16, what is the subnet address?
As the solution mentions, we need to AND the mask and IP. The first two octets we know represent the network address of the class B IP. From the given mask, in the third octet, there are five bits for the sub-network, meaning the subnetwork of the given IP has the value 16. So the sub-network would be 130.40.16.x .
The mentioned answer 130.40.32.0 would be true if the third octet in the mask was 255.
Comments welcome.
Regarding 2… the answer 130.40.32.0 is correct for the host 130.40.32.16….
130.40.32.0(network) -> 130.40.39.255(broadcast)
1.physical layer
2.datalink layer
3.network layer
4.transport layer
5.session layer
6.presention layer
7.application layer
the address range is correct in that Subnetting Question .
count in the blocks of 16.
130.40.16.0 - 130.40.31.255
130.40.32.0 - 130.40.47.255
130.40.48.0 - 130.40.63.255
and so on…
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Network Connections :ncpa.cpl
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Iexpress Wizard :iexpress
Internet Properties :inetcpl.cpl